2N5089TA Overview

In this device, the DC current gain is 400 @ 100μA 5V, which is calculated by taking the ratio of the base current to collector current and dividing transistor by two.In VCE saturation, Ic is at its maximum value (saturated), and the vce saturation (Max) is 500mV @ 1mA, 10mA.Keeping the emitter base voltage at 4.5V allows for a high level of efficiency.According to definition, current rating describes the maximum current a fuse can carry indefinitely without deteriorating too much, and this device has no current rating.During maximum operation, collector current can be as low as 100mA volts.

2N5089TA Features

the DC current gain for this device is 400 @ 100μA 5V
the vce saturation(Max) is 500mV @ 1mA, 10mA
the emitter base voltage is kept at 4.5V
the current rating of this device is 100mA

2N5089TA Applications

There are a lot of ON Semiconductor 2N5089TA applications of single BJT transistors.

• Inverter
• Driver
• Muting
• Interface