KSC1845EBU Overview

In this device, the DC current gain is 400 @ 1mA 6V, which is calculated by taking the ratio of the base current to collector current and dividing transistor by two.The collector emitter saturation voltage is 70mV, giving you a wide variety of design options.VCE saturation indicates Ic is at maximum level (saturated), whereas vce saturation (Max) indicates there is no saturation.Emitter base voltages of 5V can achieve high levels of efficiency.A fuse's current rating indicates how much current it will be able to carry over an indefinite period, and this device has a current rating of (50mA).During maximum operation, collector current can be as low as 50mA volts.

KSC1845EBU Features

the DC current gain for this device is 400 @ 1mA 6V
a collector emitter saturation voltage of 70mV
the vce saturation(Max) is 300mV @ 1mA, 10mA
the emitter base voltage is kept at 5V
the current rating of this device is 50mA

KSC1845EBU Applications

There are a lot of ON Semiconductor KSC1845EBU applications of single BJT transistors.

• Muting
• Inverter
• Interface
• Driver