KSB744YSTU Overview

The DC current gain is the ratio of the base current to the collector current βdc = Ic/Ib and the DC current gain for this device is 160 @ 500mA 5V.A VCE saturation (Max) of 2V @ 150mA, 1.5A means Ic has reached its maximum value(saturated).Keeping the emitter base voltage at -5V can result in a high level of efficiency.In definition, current rating refers to the maximum current a fuse can carry for an indefinite period without deteriorating too much, and the current rating of this device is -3A.Collector current can be as low as 3A volts at its maximum.

KSB744YSTU Features

the DC current gain for this device is 160 @ 500mA 5V
the vce saturation(Max) is 2V @ 150mA, 1.5A
the emitter base voltage is kept at -5V
the current rating of this device is -3A

KSB744YSTU Applications

There are a lot of ON Semiconductor KSB744YSTU applications of single BJT transistors.

• Inverter
• Muting
• Driver
• Interface