KSP43BU Overview

This device has a DC current gain of 40 @ 30mA 10V, which is the ratio between the collector current and the base current.The collector emitter saturation voltage is 500mV, giving you a wide variety of design options.VCE saturation indicates Ic is at maximum level (saturated), whereas vce saturation (Max) indicates there is no saturation.The base voltage of the emitter can be kept at 6V to achieve high efficiency.Normally, a fuse's current rating refers to how much current it can carry without deteriorating too much, which in this case is 500mA.As you can see, the part has a transition frequency of 50MHz.When collector current reaches its maximum, it can reach 500mA volts.

KSP43BU Features

the DC current gain for this device is 40 @ 30mA 10V
a collector emitter saturation voltage of 500mV
the vce saturation(Max) is 500mV @ 2mA, 20mA
the emitter base voltage is kept at 6V
the current rating of this device is 500mA
a transition frequency of 50MHz

KSP43BU Applications

There are a lot of ON Semiconductor KSP43BU applications of single BJT transistors.

• Muting
• Driver
• Inverter
• Interface