FJP5355TU Overview

As dc = Ic/Ib, DC current gain is the ratio of base current to collector current, and DC current gain for this device is 7 @ 2.5A 2V.A VCE saturation (Max) of 400mV @ 800mA, 2.5A means Ic has reached its maximum value(saturated).Keeping the emitter base voltage at 14.5V can result in a high level of efficiency.A fuse's current rating indicates how much current it will be able to carry over an indefinite period, and this device has a current rating of (5A).TO-220-3 is the supplier device package for this product.Collector Emitter Breakdown occurs at 440VV - Maximum voltage.Collector current can be as low as 5A volts at its maximum.

FJP5355TU Features

the DC current gain for this device is 7 @ 2.5A 2V
the vce saturation(Max) is 400mV @ 800mA, 2.5A
the emitter base voltage is kept at 14.5V
the current rating of this device is 5A
the supplier device package of TO-220-3

FJP5355TU Applications

There are a lot of ON Semiconductor FJP5355TU applications of single BJT transistors.

• Interface
• Driver
• Inverter
• Muting