KSP55TA Overview

As the DC current gain is the ratio of the collector current to the base current, for this device the DC current gain is 50 @ 100mA 1V.The collector emitter saturation voltage is -250mV, giving you a wide variety of design options.Single BJT transistor means that Ic is at Single BJT transistors maximum value (saturated), so the vce saturation(Max) is equal to 250mV @ 10mA, 100mA.Emitter base voltages of -4V can achieve high levels of efficiency.Fuse current ratings refer to how much current the fuse can carry for an indefinite period without deteriorating too much, and this device has a current rating of -500mA.There is a transition frequency of 50MHz in the part.The breakdown input voltage is 60V volts.Maximum collector currents can be below 500mA volts.

KSP55TA Features

the DC current gain for this device is 50 @ 100mA 1V
a collector emitter saturation voltage of -250mV
the vce saturation(Max) is 250mV @ 10mA, 100mA
the emitter base voltage is kept at -4V
the current rating of this device is -500mA
a transition frequency of 50MHz

KSP55TA Applications

There are a lot of ON Semiconductor KSP55TA applications of single BJT transistors.

• Muting
• Inverter
• Interface
• Driver