KSP05TA Overview

In this device, the DC current gain is 50 @ 100mA 1V, which is calculated by taking the ratio of the base current to collector current and dividing transistor by two.With a collector emitter saturation voltage of 250mV, it offers maximum design flexibility.In VCE saturation, Ic is at its maximum value (saturated), and the vce saturation (Max) is 250mV @ 10mA, 100mA.Emitter base voltages of 4V can achieve high levels of efficiency.Its current rating is 500mA, which means that it can sustain a maximum current for an indefinite period of time without degrading too much.100MHz is present in the transition frequency.There is a breakdown input voltage of 60V volts that it can take.Maximum collector currents can be below 500mA volts.

KSP05TA Features

the DC current gain for this device is 50 @ 100mA 1V
a collector emitter saturation voltage of 250mV
the vce saturation(Max) is 250mV @ 10mA, 100mA
the emitter base voltage is kept at 4V
the current rating of this device is 500mA
a transition frequency of 100MHz

KSP05TA Applications

There are a lot of ON Semiconductor KSP05TA applications of single BJT transistors.

• Muting
• Driver
• Inverter
• Interface