KSP42BU Overview

This device has a DC current gain of 40 @ 30mA 10V, which is the ratio between the base current and the collector current.A collector emitter saturation voltage of 500mV ensures maximum design flexibility.Saturation of VC means the Ic value is at its maximum, so vce saturation (Max) is 500mV @ 2mA, 20mA.A high level of efficiency can be achieved if the base voltage of the emitter remains at 6V.Current rating refers to the maximum current a fuse can carry for an indefinite period without deteriorating substantially, and this device has a 500mA current rating.In the part, the transition frequency is 50MHz.Single BJT transistor is possible to have a collector current as low as 500mA volts at Single BJT transistors maximum.

KSP42BU Features

the DC current gain for this device is 40 @ 30mA 10V
a collector emitter saturation voltage of 500mV
the vce saturation(Max) is 500mV @ 2mA, 20mA
the emitter base voltage is kept at 6V
the current rating of this device is 500mA
a transition frequency of 50MHz

KSP42BU Applications

There are a lot of ON Semiconductor KSP42BU applications of single BJT transistors.

• Driver
• Interface
• Muting
• Inverter